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Chromosomal transfer begins at a break in the chromosomal DNA adjacent to inserted F-plasmid. The entire chromosome can be transferred from the male to the female cell, and the F-plasmid region is the last part to be transferred. At 37°C complete transfer of the chromosome take 100 minutes. |
An amazing answer. Knowing that 1 base pair of DNA is 0.34 nanometers long, the E. coli genome is ~4,640,000 base pairs in length, and that it take ~100 minutes to transfer a complete copy of the genome from donor to recipient cell.
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Elie Wollman and Francois Jacob exploited this fragility to define the order of genes on the bacterial chromosome. They mixed Hfr (male) and female cells and at a various times used a short pulse with a Waring blender to shear conjugating cells apart. Because every cell of a particular Hfr strain has the F-plasmid integrated at the same site, there is a distinct, and reproducible time from the moment of conjugation to the time when specific genes are transferred to the recipient. After the transfer, the donor genes are recombined into the recipient chromosome, replacing the original alleles. |
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The key to using conjugation and recombination to map the position of genes along the chromosome is that the process generates new combinations of phenotypes at high frequency. While these 'recombinant' phenotypes could arise by multiple mutations in the recipient strain, this is extremely unlikely How unlikely is it?:
Assume the mutation frequency is 10^-6 per cell for each locus,
What is the probability of obtaining three mutations spontaneously?
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Mapping lac-/rob- mutationsWith our lac- and rob- mutations in hand, we need to answer a few questions. 1. Where do these mutations
map on the E. coli chromosome? 2. Do lac- and rob- mutation map to the same or different regions of the chromosome?
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revised 9 July 2003 |